Code39Ext.py

Go to the documentation of this file.

'''
Copyright (C) 2007 Martin Owens

This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 2 of the License, or
(at your option) any later version.

This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU General Public License for more details.

You should have received a copy of the GNU General Public License
along with this program; if not, write to the Free Software
Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA  02111-1307  USA
'''

import Code39

encode = list('ABCDEFGHIJKLMNOPQRSTUVWXYZ')

map = {}

i = 0
for char in encode:
    map[char] = i
    i = i + 1

# Extended encoding maps for full ASCII Code93
def getMap(array):
    result = {}
    y = 0
    for x in array:
        result[chr(x)] = encode[y]
        y = y + 1

    return result;

# MapA is eclectic, but B, C, D are all ASCII ranges
mapA = getMap([27,28,29,30,31,59,60,61,62,63,91,92,93,94,95,123,124,125,126,127,0,64,96,127,127,127]) # %
mapB = getMap(range(1, 26)) # $
mapC = getMap(range(33, 58)) # /
mapD = getMap(range(97, 122)) # +

class Object(Code39.Object):
    def encode(self, text):
        # We are only going to extend the Code39 barcodes
        result = ''
        for char in text:
            if mapA.has_key(char):
                char = '%' + mapA[char]
            elif mapB.has_key(char):
                char = '$' + mapB[char]
            elif mapC.has_key(char):
                char = '/' + mapC[char]
            elif mapD.has_key(char):
                char = '+' + mapD[char]
            result = result + char

        return Code39.Object.encode(self, result);